I
am going to introduce you to some new sorts of
numbers. We shall think of them as different families
of numbers. Some of these new families won't have
unique prime building blocks. We are very familiar
with the family consisting of the ordinary numbers
…-3,-2,-1,0,1,2,3… But there are other
families of numbers which mathematicians actually
stumbled on in their endeavours to solve Fermat's
Last Theorem. Consider for example all numbers
of the form A+B 2 where A and B are whole numbers.
(When I write B 2 this is the number B times 2.)
So this family includes a number like 1+3 2
which is approximately 5.24264… But the
special character of these numbers is more transparent
if we stick to writing them as 1+3 2.
What makes a collection
of numbers like this particularly nice is that
I can add or multiply them together and I won't
get any numbers which are outside the family.
For example
(1+ 2)+(3+4 2)=4+5 2
(1+ 2)x(3+4 2)=(3+ 2x(4 2)) +(4+3) 2=11+7 2.
In this last line I've slipped in a bit of algebra
which requires you to know that (A+B)x(C+D)=AxC+BxD+AxD+BxC.
This is as complicated as any of the algebra we'll
need is going to get. Don't despair if the sight
of such equations makes your eyes glaze over.
It justifies that we really won't get any numbers
outside of our family of numbers like A+B 2.
So these numbers work like
ordinary numbers in that we can add and multiply
them together. They also have a concept of prime
building blocks like ordinary numbers and in this
family built from 2 the building blocks of each
number are unique. But if we change the square
root of 2 to something different, suddenly we
find examples where numbers can be written in
two different ways as products of prime building
blocks.
To find such a family, let's
turn the screw one more time. Consider the family
of numbers of the form A+B -6 where A and B are
whole numbers. Notice that these are now imaginary
numbers
Using Gauss’s map
of the imaginary numbers, we now have a picture
where we can "see" our new numbers like
3+ -6.
This number is the point reached by moving 3 steps
east-west followed by 6
(which is approximately 2.44949) moves in the
north-south direction. We are using here that
-6= 6
x v-1, or more generally that (AxB)=( A)
x ( B).
So the imaginary bit -6
is broken up into a normal number 6
and this new imaginary number i= -1
which we interpret as heading one unit north in
our expanded worldview of numbers.

How do we do arithmetic
with these numbers? Addition is straightforward.
Each number A+B -6 we can think of as a set of
directions in this imaginary world: A steps east-west,
followed by (B times 6) moves in the north-south
direction. If I gave you two sets of directions
A+B -6 and C+D -6 you do one followed by another
and end up at a third point which you could have
got to by being given the one direction (A+C)+(B+D) -6.
This number is then the sum of the two original
numbers. So for example here is a picture of (3+ -6)+(1+2 -6)=(4+3 -6):

Multiplication is a little
trickier. We can take the algebraic route offered
by the way we saw the numbers A+B 2 being multiplied
together:
(A+B -6)x(C+D -6)
=(AC-6BD)+(AD+BC) -6.
For those interested in
the algebra, note we are using that -6 times
-6 is -6 since this was the definition of this
imaginary number.
Notice though that this
family of numbers of the form A+B -6 doesn’t
get any bigger when we add or multiply them together.
The important thing for
us now about these new sort of numbers A+B -6
where A and B are whole numbers is that we have
two essentially different ways to write numbers
as products of building blocks. An easy example
is
( -6)x( -6)=-6= -2x3.
But maybe we can crack these numbers down further.
For example in ordinary numbers consider the case
of 14x10=140=4x35. In this case we hadn't hit
the prime building blocks yet. One more step and
both sides of the equation gave us 2,2,5 and 7.
However unlike the case of 140, -6, 2 and 3 are
all numbers which can't be split any further if
we restrict ourselves to using numbers of the
form (A+B -6) where A and B are whole numbers.
This is not so obvious given
that we have allowed ourselves more possibilities
for how to split numbers. After all, with more
room to manoeuvre in this two dimensional picture,
perhaps we can split these numbers further. Actually
a picture will help here. These new numbers we
think of as a collection of points in our two
dimensional picture, where each number is got
by going a certain number of units east-west then
north-south. Lets mark all the points which are
close to the 0 point in our picture:

Take one of the three points
-2, 3 and -6 in this picture, for example -6.
Let's show that it is an indivisible building
block. Is there any way you could find two numbers
closer to 0 which multiplied together got you
to -6? A quick check inside the circle through
-6 soon reveals that it is impossible to get
to -6 by multiplying two other numbers closer
to zero in this picture.

Hence -6 must be an indivisible
building block in this set of numbers. The same
analysis will reveal -2 and 3 are also indivisible.
This makes them building blocks in this set of
numbers. (Mathematicians won't call these prime
building blocks because they only like to give
them the name prime if there is unique way to
decompose numbers. Mathematicians refer to these
indivisible building blocks as irreducible numbers.)
Here is a picture of some
the building blocks in this family of numbers
A+B -6. Like the ordinary primes not a particularly
orderly picture. In fact you might be forgiven
for thinking this picture was produced by some
fractal formula.

If you were brave enough
to negotiate the proof that normal numbers do
have unique sets of prime building blocks then
the test of your understanding is to follow the
same argument for our new set of numbers which
doesn't have unique factorisation. Where does
the argument break down? What do we mean by a
smallest rogue here? Well, one nearest to the
starting point 0 might suffice. But look back
at how we made our rogue smaller in that proof.
We chose p(1) to be the smallest prime appearing
in either expression for the smallest rogue number
N. Then we waved our wand and considered (q(1)-p(1))xq(2)x…xq(S),
a number which was smaller than N. But in our
two dimensional picture this magic doesn't work.
Remember we had
( -6)x( -6)=-6= -2x3.
The number 2 is the nearest point to 0. But if
we walk two paces east or west of the point at
-6 we always move further away from 0. So in
this two-dimensional world, we can't seem to shift
down to cases we've already covered.
The fact that certain types
of numbers like the family A+B -6 don't have a
unique way to dismantle them into building blocks
turned out to be one of the major hurdles in proving
Fermat's Last Theorem. If it had been true it
would have been Cauchy, Lamé or Kummer
in the 19th century and not Wiles who picked up
the coveted scalp of proving Fermat's tantilizing
conjecture. Indeed some believe that this might
be behind Fermat's belief that he had a proof
of his Last Theorem, that he had mistakenly believed
that all these numbers had unique factorisation.
Mathematicians have a way
of giving families of numbers a score according
to how badly they fail to have unique factorization
into building blocks. The higher the score, the
worse they behave. For example, according to this
measure the family A+B -6 scores a 2.
Those well-behaved families
which have unique factorisation like our ordinary
numbers get the coveted score of one. But were
there any such families beyond the ordinary numbers?
Gauss made the remarkable discovery that these
families have something to do about the special
equations that Euler had discovered which produced
so many primes. Euler was amazed to find that
the equation X2+X+41 produced a list
of 40 primes when fed the numbers from 0 to 39.
The same happened if he took instead of 41, the
equation X2+X+Q where Q=2,3,5,11 or
17. Gauss realised that the same Q could be used
to build families of numbers with unique factorization
into building blocks. He showed that like the
ordinary numbers, the family of numbers A+B (1-4Q)
had unique building blocks. (There is a slight
twist here. The numbers A and B should be not
just whole numbers but can also both be whole
numbers plus 1/2, e.g. A=1+1/2 and B=3+1/2. Why?
Because it turns out that multiplying and adding
this larger family still doesn’t get you
outside this family.) Gauss conjectured that in
addition to these six families, the only other
families of numbers A+B -D
to score a one for uniquely factorising were D=1,2
and 3. Remarkably it took over 160 years to prove
that Gauss was right. Between 1966 and 1967 the
Cambridge mathematician Alan Baker and the American
Harold Stark proved that Gauss had indeed found
the only families of numbers A+B -D
that scored a one for uniquely factorising.
Answering a problem
that goes back to Euler or Gauss is generally
considered as a true mark of a mathematician's
metal. If you can knock off one of Hilbert's 23
problems too before the age of 40 then you're
a dead cert for a Field's medal as Baker discovered.
Baker had found a way to generalize Gelfond and
Schneider's solution to the seventh problem on
Hilbert's list. Hilbert had mistakenly believed
that the seventh would outlast both the Riemann
Hypothesis and Fermat's Last Theorem.
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